-2x^2+16x+7=2-2x

Solution for -2x^2+16x+7=2-2x equation:

-2x^2+16x+7=2-2x

We move all terms to the left:

-2x^2+16x+7-(2-2x)=0

We add all the numbers together, and all the variables

-2x^2+16x-(-2x+2)+7=0

We get rid of parentheses

-2x^2+16x+2x-2+7=0

We add all the numbers together, and all the variables

-2x^2+18x+5=0

a = -2; b = 18; c = +5;
Δ = b2-4ac
Δ = 182-4·(-2)·5
Δ = 364
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{364}=\sqrt{4*91}=\sqrt{4}*\sqrt{91}=2\sqrt{91}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(18)-2\sqrt{91}}{2*-2}=\frac{-18-2\sqrt{91}}{-4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(18)+2\sqrt{91}}{2*-2}=\frac{-18+2\sqrt{91}}{-4}
$